Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
ಆದರೆ | 3093 | 82 | 3 | 27.3333 |
ಆಗ | 553 | 19 | 1 | 19.0000 |
ಇವುಗಳ | 282 | 14 | 1 | 14.0000 |
ಎರಡೂ | 408 | 13 | 1 | 13.0000 |
ಕಳೆದ | 188 | 13 | 1 | 13.0000 |
ವರದಿ | 164 | 11 | 1 | 11.0000 |
ಸಾಮರ್ಥ್ಯವನ್ನು | 145 | 9 | 1 | 9.0000 |
ಇಲ್ಲಿನ | 261 | 9 | 1 | 9.0000 |
ಸೆಪ್ಟೆಂಬರ್ | 188 | 9 | 1 | 9.0000 |
ಇವರ | 677 | 33 | 4 | 8.2500 |
ಇಂಗ್ಲಿಷ್ | 217 | 8 | 1 | 8.0000 |
ಇನ್ನು | 189 | 7 | 1 | 7.0000 |
ಇವನ | 205 | 7 | 1 | 7.0000 |
ದೇವಾಲಯದ | 142 | 7 | 1 | 7.0000 |
ಚದರ | 68 | 7 | 1 | 7.0000 |
ರಸ್ತೆ | 126 | 7 | 1 | 7.0000 |
ಸಲಹೆ | 92 | 7 | 1 | 7.0000 |
ಮರಣ | 100 | 7 | 1 | 7.0000 |
ಮುಂತಾದ | 538 | 21 | 3 | 7.0000 |
ಉಂಟು | 203 | 7 | 1 | 7.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
ಮಾಡಿದರು | 650 | 2 | 41 | 0.0488 |
ಭಾಗದಲ್ಲಿ | 264 | 1 | 20 | 0.0500 |
ಮಾಡಿದ್ದಾರೆ | 199 | 1 | 14 | 0.0714 |
ಕಡೆ | 231 | 1 | 12 | 0.0833 |
ಜನಿಸಿದರು | 253 | 1 | 12 | 0.0833 |
ಕಿ | 329 | 2 | 24 | 0.0833 |
ತಿಂಗಳಲ್ಲಿ | 99 | 1 | 11 | 0.0909 |
ಸಂಖ್ಯೆಯ | 159 | 1 | 11 | 0.0909 |
ನಡೆಯುತ್ತದೆ | 199 | 1 | 10 | 0.1000 |
ಮೇರೆಗೆ | 106 | 1 | 10 | 0.1000 |
ಕ್ಷೇತ್ರದಲ್ಲಿ | 182 | 1 | 9 | 0.1111 |
ಬಂದರು | 152 | 1 | 9 | 0.1111 |
ಮಹಿಳಾ | 160 | 1 | 9 | 0.1111 |
ಹಂತದ | 107 | 1 | 9 | 0.1111 |
ಬಂದಿತು | 123 | 1 | 9 | 0.1111 |
ಸ್ಥಳಗಳಲ್ಲಿ | 109 | 1 | 9 | 0.1111 |
ನೀಡಿದರು | 276 | 3 | 25 | 0.1200 |
ನಿಂದ | 348 | 1 | 8 | 0.1250 |
ಒಂದಾಗಿದೆ | 142 | 1 | 8 | 0.1250 |
ಅವಧಿಯಲ್ಲಿ | 434 | 3 | 24 | 0.1250 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II